8x^2=320-24x

Solution for 8x^2=320-24x equation:

8x^2=320-24x

We move all terms to the left:

8x^2-(320-24x)=0

We add all the numbers together, and all the variables

8x^2-(-24x+320)=0

We get rid of parentheses

8x^2+24x-320=0

a = 8; b = 24; c = -320;
Δ = b2-4ac
Δ = 242-4·8·(-320)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-104}{2*8}=\frac{-128}{16}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+104}{2*8}=\frac{80}{16}
=5
$